Diana has available 320 yards of fencing and wishes to enclose a rectangular area. Question: Diana has available 160 yards of fencing and wishes to enclose a rectangular area (a)Express the area A of the rectangle as a function of the width W of the rectangle. In a rectangle, opposite sides are equal in Jun 28, 2025 · Diana has available 160 yards of fencing and wishes to enclose a rectangular area. a) Express the area A of the rectangle as a function of the width W of the rectangle. Jun 13, 2022 · VIDEO ANSWER: Hello everyone, there is a question given. Dec 10, 2023 · The maximum area Diana can enclose with 200 yards of fencing is found by expressing the area as a function of the width, determining the width that produces the largest area using the vertex formula for a parabola, and then calculating the area with that width, which results in a maximum area of 2500 square yards when the width is 50 yards. Oct 5, 2023 · The area of a rectangle, A, can be expressed as a **function **of the width, W, when given the amount of available fencing. There are 320 yards of fencing available to enclose a rectangular field. Mar 2, 2025 · Diana has 1600 yards of fencing and wishes to enclose a rectangular area. (b) For what value of W is the area largest? (c) What is the maximum area? (a) A (W)= Asked in United States Feb 25, 2025 · Diana has available 200 yards of fencing and wishes to enclose a rectangular area. b) For what value of W is the area the largest? c) What is the maximum area? Diana has available 320 yards of fencing and wishes to enclose a rectangular area. (b) For what value of W is the area largest? Question: Diana has available 520 yards of fencing and wishes to enclose a rectangular area. For what value of W is the area largest? Aug 2, 2017 · In the given problem, we wish to find a rectangular area that can be enclosed by 320 yards of fencing that maximizes the area. To find the area, we need to consider the perimeter of the rectangle, which is equal to the sum of the lengths of all four sides. Let's designate the rectangular area's width and length as x and y respectively. ork: Section 3. Nov 1, 2016 · Diana has available 120 yards of fencing and wishes to enclose a rectangular area. For what value of w is the area largest? What is the maximum area? Sketch the graph of A(w). 4 Question 5, 3. Question: Diana has available 400 yards of fencing and wishes to enclose a rectangular area. a. a). . To find the area A of the rectangle as a function of its width W, we start with the perimeter equation that involves the total amount of fencing David has. b). (a) Express the area A of the rectangle as a function of the width W of the rectangle. Diana has available 120 yards of fencing and wishes to enclose a rectangular area. How should this fencing be used so that the enclosed area is as large as possible? Let the length of the rectangle be L and the width be W. (b) For what value of W is the area largest? (c) What is the maximum area? Dec 10, 2023 · The maximum area Diana can enclose with 200 yards of fencing is found by expressing the area as a function of the width, determining the width that produces the largest area using the vertex formula for a parabola, and then calculating the area with that width, which results in a maximum area of 2500 square yards when the width is 50 yards. Sep 21, 2023 · David has 800 yards of fencing available and wishes to enclose a rectangular area. (a) Express the area A of the rectangle as a function of the width w of the rectangle. The answer is very well known fact: under given condition, the maximum area is provided by the square, and when the perimeter of a rectangle is given (= the fence length), the side of this square is one fourth of the perimeter. b. (a) Express the area A of the rectangle as a function of the width W of the rectangle (b) For what value of W is the area largest? Question: David has available 800 yards of fencing and wishes to enclose a rectangular area. In first part we have asked, express the area of the rectangle as a function of the width, W of the Diana has available 200 yards of fencing and wishes to enclose a rectangular area. Diana has available 5 . Mar 11, 2020 · Diana has available 1600 yards of fencing and wishes to enclose a rectangular area. The perimeter of the rectangle is given by: P = 2L + 2W But we know that the total amount of fencing available is 320 yards, so: 2L + 2W = 320 Simplifying this equation, we get: L + W = 160 Express the area A of the rectangle as a function of the width W: Given that the total fencing is 320 yards, we have the equation 320 = 2L + 2W, where L is the length and W is the width of the rectangle. Diana has available 320 yards of fencing and wishes to enclose a rectangular area. Diana has available 1600 yards of fencing and wishes to enclose a rectangular area. Question: Diana has available 320 yards of fencing and wishes to enclose a rectangular area. Express the area A of the rectangle as a function of the width w of the rectangle. David has available 400 yards of fencing and wishes to enclose a rectangular area. 20 yards of fencing and besiex to enclose a rectangular area. In this case, Diana has 280 yards of fencing. Aug 4, 2023 · David has 400 yards of fencing available and wishes to enclose a rectangular area. Solving for L, we get L = 160 - W. b) For what value of W is the area the largest? c) What is the maximum area? Jun 2, 2023 · Diana has 40 yards of fencing available and wishes to enclose a rectangular area. (b) For what value of W is the area largest? (c) What is the maximum area? Diana has 240 yards of fencing and wishes to enclose a rectangular area. 7 Part 2 of 3 Diana has available 320 yards of fencing and wishes to enclose a rectangular area. In a rectangle, opposite sides are equal in Mar 11, 2020 · Diana has available 1600 yards of fencing and wishes to enclose a rectangular area. The formula for the perimeter P of a rectangle is given by: where L is the length and W is the width. list (a) Express the area A of the rectangle as a function of the width W of the rectangle. Express the area A of the rectangle as a function of the width W of the rectangle. 4. gcok2 k58ss clbqyh bwd tuv 6oxrpi mg oyx96 2nyhhu phee